Có :
\(3+\sqrt{5}=\dfrac{6+2\sqrt{5}}{2}=\dfrac{5+2\sqrt{5}+1}{2}=\dfrac{\left(\sqrt{5}+1\right)^2}{2}\)
\(3-\sqrt{5}=\dfrac{6-2\sqrt{5}}{2}=\dfrac{512\sqrt{5}+1}{2}=\dfrac{\left(\sqrt{5}-1\right)^2}{2}\)
=> \(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
\(=\dfrac{\sqrt{5}-1}{\sqrt{2}}+\dfrac{\sqrt{5}+1}{\sqrt{2}}\)
\(=\dfrac{2\sqrt{5}}{\sqrt{2}}=\sqrt{10}\)