Bài 1:
a: 2x+6=0
=>2x=-6
hay x=-3
b: \(\left(x-1\right)^2-4=0\)
=>(x-1-2)(x-1+2)=0
=>(x-3)(x+1)=0
=>x=3 hoặc x=-1
c: \(\Leftrightarrow\left(x-2\right)^2+3\left(x+2\right)=x^2-11\)
\(\Leftrightarrow x^2-4x+4+3x+6=x^2-11\)
=>-x+10=-11
=>-x=-21
hay x=21


