a: \(P=\dfrac{x^2+5x+6+x^2-5x+6-2x^2-3x-6}{\left(x-2\right)\cdot\left(x+2\right)}\cdot\dfrac{x+2}{2x+1}\)
\(=\dfrac{-3x+6}{\left(x-2\right)}\cdot\dfrac{1}{2x+1}=\dfrac{-3}{2x+1}\)
b: |2x-3|=1
=>2x-3=1 hoặc 2x-3=-1
=>x=2(loại) hoặc x=1(nhận)
Khi x=1 thì \(P=\dfrac{-3}{2+1}=\dfrac{-3}{3}=-1\)
c: P>0
=>2x+1<0
=>x<-1/2