Question

Answer 1

\(=10\cdot\left(\dfrac{3}{5}+\dfrac{2}{3}\right)-\dfrac{2}{5}=10\cdot\dfrac{19}{15}-\dfrac{2}{5}=\dfrac{184}{15}\)

Answer 2

A=10 x (\(\dfrac{3}{5}+\dfrac{2}{3}\)) - \(\dfrac{3}{5}\)x\(\dfrac{2}{3}\)

A=10 x \(\dfrac{19}{15}\) - \(\dfrac{2}{5}\)

A=\(\dfrac{184}{15}\)

Answer 3

thay \(a=\dfrac{3}{5};b=\dfrac{2}{3}\) ta có : \(A=10\cdot\left(\dfrac{3}{5}+\dfrac{2}{3}\right)-\dfrac{3}{5}\cdot\dfrac{2}{3}\\ A=10\cdot\dfrac{19}{15}-\dfrac{6}{15}\\ A=\dfrac{190}{15}-\dfrac{6}{15}=\dfrac{184}{15}\)

Answer 4

\(A=10\left(a+b\right)-ab\)

Thay \(a=\dfrac{3}{5};b=\dfrac{2}{3}\) vào biểu thức, ta có:

\(A=10\left(\dfrac{3}{5}+\dfrac{2}{3}\right)-\dfrac{3}{5}\times\dfrac{2}{3}\)

\(=10\times\dfrac{19}{15}-\dfrac{2}{5}=\dfrac{184}{15}\)