Bài 2:
a: =>(x-3)(2x+5)=0
=>x=3 hoặc x=-5/2
b: =>(x-2)(x+2+3-2x)=0
=>(x-2)(5-x)=0
=>x=2 hoặc x=5
c: =>(x-1)=0
=>x=1
d: =>(2x-7)(x-2)=0
=>x=7/2 hoặc x=2
e: =>(2x-5-x-2)(2x-5+x+2)=0
=>(x-7)(3x-3)=0
=>x=7 hoặc x=1
f: =>(x-1)(x-3)=0
=>x=1 hoặc x=3
Bài 1:
\(a,\left(3x-2\right)\left(4x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x-2=0\\4x+5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{matrix}\right.\\ b,\left(4x+2\right)\left(x^2+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}4x+2=0\\x^2+1=0\left(vô.lí\right)\end{matrix}\right.\\ \Rightarrow x=-\dfrac{1}{2}\)
\(c,\left(2,3x-6,9\right)\left(0,1x+2\right)=0\\ \Rightarrow\left[{}\begin{matrix}2,3x-6,9=0\\0,1x+2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-20\end{matrix}\right.\\ d,\left(2x+7\right)\left(x-5\right)\left(5x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x+7=0\\x-5=0\\5x+1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{2}\\x=5\\x--\dfrac{1}{5}\end{matrix}\right.\)