Question

Answer 1

Bài 1a) 3x - 2 = 2x - 3

<=> 3x - 2x = -3 + 2

<=> x = -1

b) 5 - (x - 6) = 4(3 - 2x)

<=> 5 - x + 6 = 12 - 8x

<=> -x + 8x = 12 - 5 - 6

<=> 7x = 1

<=> x = 1/7

 \(c)\dfrac{3}{2}(x-\dfrac{5}{4})-\dfrac{5}{8}=x \\<=> \dfrac{3}{2}x-x=\dfrac{5}{8}+\dfrac{15}{8} \\<=>\dfrac{1}{2}x=\dfrac{5}{2} \\<=>x=5 \\d) \dfrac{10x+3}{12}=1+\dfrac{6+8x}{9} \\<=>\dfrac{30x+9}{36}=\dfrac{36}{36}+\dfrac{24+32x}{36} \)

\(\\<=>-2x=36+24-9 \\<=>-2x=51 \\<=>x=\dfrac{-51}{2}\)

Answer 2

Bài 2: 2.(-2) + k = -2 - 1

<=> k = 1

Bài 3: Xét pt 3x = 3(x + 2) <=> 0x = 6 (vô lí)

--> Pt vô nghiệm

Xét pt 2(x - 1) = 2x <=> 0x = 2 (vô lí)

--> pt vô nghiệm

Vậy 2 pt tương đương.

Answer 3