\(C1:\)
\(a.\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(Fe+\dfrac{3}{2}Cl_2\underrightarrow{t^0}FeCl_3\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)
\(b.\)
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(H_2+Cl_2\underrightarrow{t^0}2HCl\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(FeCl_2+2AgNO_3\rightarrow Fe\left(NO_3\right)_2+2AgCl\)
\(AgCl\underrightarrow{t^0}Ag+\dfrac{1}{2}Cl_2\)
\(C2:\)
\(n_{H_2}=\dfrac{2.24}{22.4}=0.1\left(mol\right)\)
\(M+2HCl\rightarrow MCl_2+H_2\)
\(0.1.................................0.1\)
\(M_M=\dfrac{5.6}{0.1}=56\left(\dfrac{g}{mol}\right)\)
\(Mlà:Fe\)
\(\)
\(C3:\)
\(n_{Fe}=n_{H_2}=\dfrac{2.016}{22.4}=0.09\left(mol\right)\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(m_{Fe}=0.09\cdot56=5.04\left(g\right)\)
\(\%Fe=\dfrac{5.04}{6.96}\cdot100\%=72.41\%\)
