\(a,\dfrac{3x}{x-5}=\dfrac{-3x}{5-x}\\ b,\dfrac{4x}{x+1}=\dfrac{4x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)};\dfrac{3x}{x-1}=\dfrac{3x\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}\\ c,\dfrac{2}{x^2+8x+16}=\dfrac{4}{2\left(x+4\right)^2};\dfrac{x-4}{2x+8}=\dfrac{\left(x-4\right)\left(x+4\right)}{2\left(x+4\right)^2}\\ d,\dfrac{2x}{\left(x+1\right)\left(x-3\right)}=\dfrac{2x\left(x-2\right)}{\left(x+1\right)\left(x-3\right)\left(x-2\right)}\\ \dfrac{x+3}{\left(x+1\right)\left(x-2\right)}=\dfrac{\left(x+3\right)\left(x-3\right)}{\left(x+1\right)\left(x-2\right)\left(x-3\right)}\)
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