1) Ta có: \(10\left(x-7\right)-8\left(x+5\right)=6\cdot\left(-5\right)+24\)
\(\Leftrightarrow10x-70-8x-40=-30+24\)
\(\Leftrightarrow2x-110=-6\)
\(\Leftrightarrow2x=104\)
hay x=52
Vậy: x=52
2) Ta có: \(8\left(x-\left|-7\right|\right)-6\left(x-2\right)=\left|-8\right|\cdot6-50\)
\(\Leftrightarrow8\left(x-7\right)-6\left(x-2\right)=48-50\)
\(\Leftrightarrow8x-56-6x+12=-2\)
\(\Leftrightarrow2x-44=-2\)
\(\Leftrightarrow2x=42\)
hay x=21
Vậy: x=21
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