Ta có: \(V=\pi\cdot r^2\cdot h\)
=>\(\pi\cdot r^2\cdot h=1\)
=>\(h=\frac{1}{\pi\cdot r^2}\)
Diện tích nguyên liệu là:
\(S=S_{xq}+S_{đáy}=\pi\cdot r^2+2\cdot\pi\cdot r\cdot h\)
\(=\pi\cdot r^2+\frac{2}{r}\)
\(=\pi\cdot r^2+\frac{1}{r}+\frac{1}{r}\ge3\cdot\sqrt[3]{\pi\cdot r^2\cdot\frac{1}{r}\cdot\frac{1}{r}}=3\sqrt[3]{\pi}\)
=>Chọn C
