Question

Answer 1

a.\(\Leftrightarrow\left(x-3\right)^2+\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x-3+1\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=2\end{matrix}\right.\)

Answer 2

\(\Rightarrow\left(x-3\right)\left(x-3+1\right)=0\\ \Rightarrow\left(x-3\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=2\end{matrix}\right.\)