\(e,=\dfrac{2\sqrt{3}-2-2\sqrt{3}-2}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}=\dfrac{-4}{2}=-2\\ f,=\dfrac{\sqrt{7}+\sqrt{2}+\sqrt{7}-\sqrt{2}}{\left(\sqrt{7}-\sqrt{2}\right)\left(\sqrt{7}+\sqrt{2}\right)}=\dfrac{2\sqrt{7}}{5}\\ g,=\dfrac{\sqrt{5}\left(2-\sqrt{7}\right)}{2-\sqrt{7}}+2\sqrt{5}=\sqrt{5}+2\sqrt{5}=3\sqrt{5}\\ h,=\dfrac{\sqrt{6}\left(\sqrt{2}+\sqrt{3}\right)}{\sqrt{2}+\sqrt{3}}-\dfrac{9\left(\sqrt{10}-1\right)}{9}=\sqrt{6}-\sqrt{10}+1\)
Đúng 2
Bình luận (0)
