Question

Giải hệ phương trình:

\(\left\{{}\begin{matrix}4x+4y=64\\-2x+5y=10\end{matrix}\right.\)

Answer 1

\(\left\{{}\begin{matrix}4x+4y=64\\-2x+5y=10\end{matrix}\right.\)⇔\(\left\{{}\begin{matrix}4x+4y=64\\4x-10y=-20\end{matrix}\right.\)⇔\(\left\{{}\begin{matrix}14y=64-\left(-20\right)\\x=\dfrac{64-4y}{4}\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}y=6\\x=10\end{matrix}\right.\)

Vậy nghiệm của hệ phương trình (x;y) = (10;6)

Answer 2

\(\left\{{}\begin{matrix}4x+4y=64\\-2x+5y=10\end{matrix}\right.\)⇔\(\left\{{}\begin{matrix}4x+4y=64\\-4x+10y=20\end{matrix}\right.\)⇔\(\left\{{}\begin{matrix}14y=64\\-4x+10y=20\end{matrix}\right.\)

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