Question

Answer 1

\(600m=0,6km;5p=\dfrac{1}{12}h;4p=\dfrac{1}{15}h\)

\(\left\{{}\begin{matrix}v'=s':t'=1:\dfrac{1}{12}=12\left(\dfrac{km.}{h}\right)\\v''=s'':t''=0,6:\dfrac{1}{15}=9\left(\dfrac{km}{h}\right)\\v=\dfrac{s'+s''}{t'+t''}=\dfrac{1+0,6}{\dfrac{1}{12}+\dfrac{1}{15}}=\dfrac{32}{3}\left(\dfrac{km}{h}\right)\end{matrix}\right.\)

Answer 2

Vận tốc của bạn Nam khi đi trên quãng đường đầu là:

_v1= \(\dfrac{S_1}{t_1}\)