Ta có \(t_1 = t_2 = t_3 = \dfrac{1}{3}t\)
\(s_1 = v_1.t_1 = 40.\dfrac{1}{3}t = \dfrac{40t}{3}\)
\(s_2 = v_2.t_2 = 30.\dfrac{1}{3}t = \dfrac{30t}{3} = 10t\)
\(s_3 = v_3.t_3 = 48.\dfrac{1}{3}t = \dfrac{48t}{3} = 16t\)
\(vtb = \dfrac{s_1 + s_2 + s_3}{t_1 + t_2 + t_3} =\dfrac{ \dfrac{40t}{3} + 10t +16t}{\dfrac{1}{3}t + \dfrac{1}{3}t + \dfrac{1}{3}t} = \dfrac{ t( \dfrac{40}{3} + 10 +16)}{t} = 39,3 km/h\)