Question

Answer 1

a) \(\sqrt{x^2+6x+9}-2x=1\\ \Rightarrow x+3-2x=1\\ \Rightarrow-x=-2\\ \Rightarrow x=2\)

Answer 2

ĐKXĐ:\(x\ge1\)

\(\sqrt{x^2+3x-2}=x-1\\ \Rightarrow\left\{{}\begin{matrix}x-1\ge0\\x^2+3x-2=x^2-2x+1\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x\ge1\\5x=3\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x\ge1\\x=\dfrac{3}{5}\left(loại\right)\end{matrix}\right.\)

Vậy pt trên vô nghiệm