Question

Answer 1

Câu 2:

PTHH: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

Ta có: \(n_{Al}=\dfrac{0,45}{27}=\dfrac{1}{60}\left(mol\right)\)

\(\Rightarrow n_{H_2}=0,025\left(mol\right)\) \(\Rightarrow V_{H_2}=0,025\cdot22,4=0,56 \left(l\right)\) 

 

Answer 2

Câu 1:

PTHH: \(Na+H_2O\rightarrow NaOH+\dfrac{1}{2}H_2\uparrow\)

Ta có: \(n_{H_2}=\dfrac{1}{2}n_{Na}=\dfrac{1}{2}\cdot\dfrac{0,557}{23}=\dfrac{557}{23000}\left(mol\right)\)

\(\Rightarrow V_{H_2}=\dfrac{557}{23000}\cdot22,4\approx0,54\left(l\right)\)