\(a,=\left(x-y\right)^2+4\left(x-y\right)+4-16\\ =\left(x-y+2\right)^2-16\\ =\left(x-y+2+4\right)\left(x-y+2-4\right)\\ =\left(x-y+6\right)\left(x-y-2\right)\)
\(b,=\left(x^2+x\right)^2+4\left(x^2+x\right)+4-16\\ =\left(x^2+x+2\right)^2-16\\ =\left(x^2+x+6\right)\left(x^2+x-2\right)\\ =\left(x-1\right)\left(x+2\right)\left(x^2+x+6\right)\)
\(c,=\left(x^2+4x+8\right)^2+x\left(x^2+4x+8\right)+2x\left(x^2+4x+8\right)+2x^2\\ =\left(x^2+4x+8\right)\left(x^2+5x+8\right)+2x\left(x^2+5x+8\right)\\ =\left(x^2+5x+8\right)\left(x^2+6x+8\right)=\left(x+2\right)\left(x+4\right)\left(x^2+5x+8\right)\)
\(d,=\left(x^2+5x+4\right)\left(x^2+5x+6\right)-24\\ =\left(x^2+5x+5\right)^2-1-24\\ =\left(x^2+5x+5\right)^2-25\\ =\left(x^2+5x+10\right)\left(x^2+5x\right)\\ =x\left(x+5\right)\left(x^2+5x+10\right)\)
Không làm tắt
Ko làm tắt
