\(a,\widehat{BIC}=180-\widehat{IBC}-\widehat{ICB}=180-\dfrac{1}{2}\widehat{ABC}-\dfrac{1}{2}\widehat{ACB}=180-\dfrac{1}{2}\left(\widehat{ABC}+\widehat{ACB}\right)=180-\dfrac{1}{2}\left(180-\widehat{A}\right)=180-\dfrac{1}{2}\cdot120=180-60=120\)
\(b,\widehat{BIC}=180-\dfrac{1}{2}\left(180-\widehat{A}\right)=180-90+\dfrac{\alpha}{2}=90+\dfrac{\alpha}{2}\)





