Question

Answer 1

ĐKXĐ: x<=2035

Ta có: \(\sqrt{2059-x}+\sqrt{2035-x}+\sqrt{2154-x}=24\)

=>\(\sqrt{2059-x}-7+\sqrt{2035-x}-5+\sqrt{2154-x}-12=0\)

=>\(\frac{2059-x-49}{\sqrt{2059-x}+7}+\frac{2035-x-25}{\sqrt{2035-x}+5}+\frac{2154-x-144}{\sqrt{2154-x}+12}=0\)

=>\(\left(2010-x\right)\left(\frac{1}{\sqrt{2059-x}+7}+\frac{1}{\sqrt{2035-x}+5}+\frac{1}{\sqrt{2154-x}+12}=0\right)\)

=>2010-x=0

=>x=2010(nhận)