Question

Answer 1

cần gấp

Answer 2

a: Ta có: \(A=\left(x+1\right)^3-4x\left(x^2+2x-5\right)\)

\(=x^3+3x^2+3x+1-4x^3-8x^2+20x\)

\(=-3x^3-5x^2+23x+1\)

b: Ta có: \(B=2x^2\left(x+3\right)-\left(x^2+x-5\right)+\left(x-2\right)^3\)

\(=2x^3+6x^2-x^2-x+5+x^3-6x^2+12x-8\)

\(=3x^3-x^2+11x-3\)

c: Ta có: \(C=\left(x-2\right)\left(x^2+2x+4\right)-\left(x^2+2\right)\left(x-1\right)\)

\(=x^3-8-x^3+x^2-2x+2\)

\(=x^2-2x-6\)

d: Ta có: \(\left(x-3\right)\left(x^2+3x+9\right)-\left(x+2\right)\left(x^2-2x+4\right)\)

\(=x^3-27-x^3+8\)

=-19