a) Ta có: \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
\(=\left(4+\sqrt{15}\right)\cdot\left(\sqrt{5}-\sqrt{3}\right)^2\)
\(=\dfrac{\left(8+2\sqrt{15}\right)\left(8-2\sqrt{15}\right)}{2}\)
\(=\dfrac{64-60}{2}=\dfrac{4}{2}=2\)

