Question

Answer 1

a) Ta có: \(\sqrt{5}-\sqrt{48}+5\sqrt{27}-\sqrt{45}\)

\(=\sqrt{5}-4\sqrt{3}+15\sqrt{3}-3\sqrt{5}\)

\(=11\sqrt{3}-2\sqrt{5}\)

b) Ta có: \(2\sqrt{3}+\sqrt{48}-\sqrt{75}-\sqrt{243}\)

\(=2\sqrt{3}+4\sqrt{3}-5\sqrt{3}-9\sqrt{3}\)

\(=-8\sqrt{3}\)

c) Ta có: \(3\sqrt{50}-2\sqrt{75}-\dfrac{4\sqrt{54}}{\sqrt{3}}-3\cdot\sqrt{\dfrac{1}{3}}\)

\(=15\sqrt{2}-10\sqrt{3}-12\sqrt{2}-\sqrt{3}\)

\(=3\sqrt{2}-11\sqrt{3}\)

d) Ta có: \(\dfrac{1}{2}\sqrt{50}-2\sqrt{96}-\dfrac{\sqrt{30}}{\sqrt{15}}+12\sqrt{\dfrac{1}{6}}\)

\(=\dfrac{5}{2}\sqrt{2}-8\sqrt{6}-\sqrt{2}+2\sqrt{6}\)

\(=\dfrac{3}{2}\sqrt{2}-6\sqrt{2}\)