a) Ta có: \(A=\left(\dfrac{\sqrt{x}+10}{x+\sqrt{x}-2}+\dfrac{\sqrt{x}-2}{\sqrt{x}-1}-\dfrac{\sqrt{x}+1}{\sqrt{x}+2}\right):\dfrac{1}{\sqrt{x}-1}\)
\(=\left(\dfrac{\sqrt{x}+10+x-4-x+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}\right)\cdot\dfrac{\sqrt{x}-1}{1}\)
\(=\dfrac{\sqrt{x}+7}{\sqrt{x}+2}\)

