PT: \(FeO+2HCl\rightarrow FeCl_2+H_2O\)
\(ZnO+2HCl\rightarrow ZnCl_2+H_2O\)
a, Giả sử: \(\left\{{}\begin{matrix}n_{FeO}=x\left(mol\right)\\n_{ZnO}=y\left(mol\right)\end{matrix}\right.\)
⇒ 72x + 81y = 67,95 (1)
Theo PT: \(\left\{{}\begin{matrix}n_{FeCl_2}=n_{FeO}=x\left(mol\right)\\n_{ZnCl_2}=n_{ZnO}=y\left(mol\right)\end{matrix}\right.\)
⇒ 127x + 136y = 114,7 (2)
Từ (1) và (2) \(\Rightarrow\left\{{}\begin{matrix}x=0,1\left(mol\right)\\y=0,75\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{FeO}=\dfrac{0,1.72}{67,95}.100\%\approx10,6\%\\\%m_{ZnO}\approx89,4\%\end{matrix}\right.\)
b, Theo PT: \(n_{HCl}=2n_{FeO}+2n_{ZnO}=1,7\left(g\right)\)
\(\Rightarrow m_{HCl}=1,7.36,5=62,05\left(g\right)\)
\(\Rightarrow m_{ddHCl}=\dfrac{62,05}{3,65\%}=1700\left(g\right)\)
c, Ta có: m dd sau pư = 67,95 + 1700 = 1767,95 (g)
\(\Rightarrow\left\{{}\begin{matrix}C\%_{FeCl_2}=\dfrac{0,1.127}{1767,95}.100\%\approx0,72\%\\C\%_{ZnCl_2}=\dfrac{0,75.136}{1767,95}.100\%\approx5,77\%\end{matrix}\right.\)
Bạn tham khảo nhé!
