Tìm GTNN của \(x-2\sqrt{x-1}\) với x>=1

\(3\sqrt{2x-1}=2x-5\)

\(5\sqrt{x-2}=x+2\)

\(\sqrt{x+2}-\sqrt{2x-10}=1\)

Giải pt dùm mình nha. thanks

Rút gọn: \(\frac{\sqrt{X^2-4x+4}}{X-2}\) với X<2

\(\frac{\sqrt{9X^2-6X+1}}{9X^2-1}\) với X>1/3

A\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{2015}-\frac{1}{2016}\)

A=\(\frac{1}{1}+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{2015}-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{2016}\right)\)

A=\(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2015}+\frac{1}{2016}-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{2016}\right)\)

A=\(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2015}+\frac{1}{2016}-\left(\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{1008}\right)\)

A=\(\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2015}+\frac{1}{2016}\)

B-A=\(\left(\frac{1}{1008}+\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2016}\right)-\left(\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2015}+\frac{1}{2016}\right)\)

B-A=1/1008

hôm qua , hôm nay , hôm kia

Hôm qua hôm nay ngày mai

1. Mrs.Lan asked me if I could carry those chairs into the house.

2. He told me to give him my book.

3. The teacher said you shouldn't make noise in class.

4. Mr.Hung asked me if I couls help Tam with his English pronunciation.

5. I love playing sports and reading books.

6. Her birthday is on May 10 th, 1996

7. Nga has to wash the dishes everyday.

8. We have studied English for 4 years.

9. Tam is the tallest student in class.

10. In the past women used to do the housework without the help of modern equipment.

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