HOC24
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Môn học
Chủ đề / Chương
Bài học
\(=\left(2\sqrt{2}+5\sqrt{2}\right).\sqrt{2}\)
\(=7\sqrt{2}.\sqrt{2}\)
\(=14\)
\(M=\dfrac{x+3+2\left(\sqrt{x}-3\right)-\left(\sqrt{x}+3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)
\(M=\dfrac{x+3+2\sqrt{x}-6-\sqrt{x}-3}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)
\(M=\dfrac{x+\sqrt{x}-6}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)
\(M=\dfrac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)
\(M=\dfrac{\sqrt{x}-2}{\sqrt{x}-3}\)
c)\(64x^2-48x+9-\left(64x^2+144x+81\right)=12\)
\(64x^2-48x-3-64x^2-144x-81=0\)
\(-192x=84\)
\(x=-\dfrac{7}{16}\)
a) \(36x^2-1-\left(36x^2-36x+9\right)=8\)
\(36x^2-1-36x^2+36x-9-8=0\)
\(36x=18\)
\(x=\dfrac{1}{2}\)
\(\dfrac{1}{2}-\left|x-3\right|=2\)
\(\left|x-3\right|=-\dfrac{3}{2}\)
\(\rightarrow\)không tìm được x thỏa mãn
a) \(=x^2+7x-12x-84-2x+14\)
\(=x^2-7x-70\)
b)\(=x^2-4x-2x+8\)
\(=x\left(x-4\right)-2\left(x-4\right)\)
\(=\left(x-4\right)\left(x-2\right)\)
c) \(=9x\left(x+y\right)-\left(x+y\right)\)
\(=\left(9x-1\right)\left(x+y\right)\)
d)\(=\left(x-y\right)^2-9^2\)
\(=\left(x-y+9\right)\left(x-y-9\right)\)
e)\(=x^2+8x+16-60+15x\)
\(=x^2+23x-44\)
a) Áp dụng định lí Pytago trong \(\Delta\) AHC vuông tại H ta có :
\(AH^2+HC^2=AC^2\)
\(\Rightarrow HC^2=AC^2-AH^2\)
\(\Rightarrow HC=\sqrt{AC^2-AH^2}=\sqrt{40^2-24^2}=32cm\)
b) Áp dụng định lí Pytago trong \(\Delta\) AHC vuông tại H ta có :
\(\Rightarrow AC=\sqrt{AH^2+HC^2}=\sqrt{9,6^2+12,8^2}=16cm\)
\(-\dfrac{1}{4}.\dfrac{4}{17}.\dfrac{-68}{21}.\dfrac{-7}{23}\)
=\(\dfrac{-1}{17}.\dfrac{68}{69}\)
=\(\dfrac{-4}{69}\)
a) X hóa trị III
b) \(X_2\left(SO_4\right)_3\)
\(\Rightarrow\sqrt{\left(x-3\right)^2}=5^2\)
\(\Rightarrow\left|x-3\right|=5\)
\(\Rightarrow x-3=5\) hoặc \(x-3=-5\)
\(\Rightarrow x=8\) \(\Rightarrow x=-2\)