ảo thế nhỉ :v

ủa sao 5+5+5=125 vậy :)))))

a)

\(5+\dfrac{3}{4}=\dfrac{20}{4}+\dfrac{3}{4}=\dfrac{23}{4}\)

b)

\(8\cdot\dfrac{5}{7}=\dfrac{40}{7}\)

c)

\(\dfrac{11}{12}\cdot\dfrac{2}{5}=\dfrac{22}{60}=\dfrac{11}{30}\)

d)

\(12:\dfrac{2}{3}=\dfrac{12}{1}\cdot\dfrac{3}{2}=\dfrac{36}{2}=18\)

e)

\(\dfrac{5}{8}:2=\dfrac{5}{8}\cdot\dfrac{1}{2}=\dfrac{5}{16}\)

g)

\(\dfrac{4}{9}:\dfrac{2}{5}=\dfrac{4}{9}\cdot\dfrac{5}{2}=\dfrac{20}{18}=\dfrac{10}{9}\)

\(\dfrac{2}{3}x+\dfrac{1}{4}x=\dfrac{-22}{27}\)

\(x.\left(\dfrac{2}{3}+\dfrac{1}{4}\right)=\dfrac{-22}{27}\)

\(x\cdot\dfrac{11}{12}=\dfrac{-22}{27}\)

\(x=-\dfrac{8}{9}\)

\(\left(\dfrac{1975}{1976}+\dfrac{2010}{2011}+\dfrac{1963}{1968}\right)\cdot\left(\dfrac{1}{3}-\dfrac{1}{4}-\dfrac{1}{12}\right)\)

\(=\left(\dfrac{1975}{1976}+\dfrac{2010}{2011}+\dfrac{1963}{1968}\right)\cdot\left(\dfrac{1}{12}-\dfrac{1}{12}\right)\)

\(=\left(\dfrac{1975}{1976}+\dfrac{2010}{2011}+\dfrac{1963}{1968}\right)\cdot0\)

= 0

độ nảy của quả bòng khi chạm đất lần đầu là

\(10\cdot\dfrac{3}{5}=6\left(m\right)\)

độ nảy của quả bóng khi chạm đất lần 2 là

\(6\cdot\dfrac{3}{5}=3,6\left(m\right)\)

độ nảy của quả bóng khi chạm đất lần 3 là

\(3,6\cdot\dfrac{3}{5}=2,16\left(m\right)\)

ds = 2,16 m

\(x+\dfrac{6}{15}=\dfrac{4}{3}\)

\(x=\dfrac{4}{3}-\dfrac{6}{15}\)

\(x=\dfrac{20}{15}-\dfrac{6}{15}\)

\(x=\dfrac{14}{15}\)

theo đề bài ta có

\(\dfrac{1}{7}< x>\dfrac{1}{6}\)

\(< =>\dfrac{5}{35}< x>\dfrac{5}{30}\)

\(=>x=\dfrac{5}{34},\dfrac{5}{33},\dfrac{5}{32},\dfrac{5}{31}\)

\(\dfrac{4}{2}=\dfrac{10}{5}=\dfrac{18}{9}=\dfrac{194}{97}=2\)

\(\dfrac{12}{3}=\dfrac{144}{36}=4\)