\(\left(\dfrac{7}{9}-\dfrac{1}{3}\right)\cdot\left[-\dfrac{5}{6}\right]:\left(2\dfrac{1}{12}\right)+\left(\dfrac{13}{5}-\dfrac{7}{10}\right)\cdot\left(6\dfrac{2}{3}\right)\cdot\left(\dfrac{1}{4}-\dfrac{3}{8}\right)\)

\(=\dfrac{4}{9}\cdot\dfrac{5}{6}:\dfrac{25}{12}+\dfrac{19}{10}\cdot\dfrac{20}{3}\cdot\left(-\dfrac{1}{8}\right)\)

\(=\dfrac{8}{45}+\left(-\dfrac{19}{12}\right)=-\dfrac{253}{180}\)

tách ra bn ơi

\(\dfrac{5}{6}:\left(\dfrac{10}{-9}\right)+\dfrac{-3}{4}\cdot\dfrac{8}{9}+12:\dfrac{24}{7}\cdot\left(\dfrac{5}{6}-\dfrac{4}{3}+\dfrac{1}{2}\right)\)

\(=-\dfrac{3}{4}+\dfrac{-2}{3}+0=-\dfrac{17}{12}\)

\(-\dfrac{5}{14}:\left(\dfrac{4}{21}-\dfrac{3}{7}\right)\cdot\left|\dfrac{-2}{3}\right|-\dfrac{3}{2}\cdot\left(\dfrac{1}{3}-\dfrac{5}{6}\right)+\dfrac{1}{5}:\left(\dfrac{-3}{10}\right)\)

\(=-\dfrac{5}{14}:\left(-\dfrac{5}{21}\right)\cdot\dfrac{2}{3}-\dfrac{3}{2}\cdot\left(-\dfrac{1}{2}\right)+\left(-\dfrac{2}{3}\right)\)

\(=1-\left(-\dfrac{3}{4}\right)+\left(-\dfrac{2}{3}\right)=\dfrac{13}{12}\)

\(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\cdot\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\cdot\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)

\(=-\dfrac{17}{26}\cdot\dfrac{1}{10}:\dfrac{17}{13}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\left(-\dfrac{33}{10}\right)\)

\(=-\dfrac{1}{20}-1+\left(-\dfrac{11}{5}\right)=-\dfrac{13}{4}\)

\(\dfrac{5}{3}\cdot\left(\dfrac{5}{6}-\dfrac{10}{9}\right):\dfrac{1}{2}-I\dfrac{-9}{5}I:I-\dfrac{18}{15}I+\dfrac{28}{15}:\left(-\dfrac{7}{10}\right)\)

\(=\dfrac{5}{3}\cdot\left(-\dfrac{5}{18}\right):\dfrac{1}{2}-\dfrac{9}{5}:\dfrac{18}{15}+\left(-\dfrac{8}{3}\right)\)

\(=-\dfrac{25}{27}-\dfrac{3}{2}+\left(-\dfrac{8}{3}\right)=-\dfrac{275}{54}\)

dấu giá trị tuyệt đối của mình nó hơi lạ một tý mong bn thông cảm :))

bùn ghê

c)

\(5^{25}.5^{21}=5^{46}\)

d)

\(6^{2023}:6^{2020}=6^3\)

a)

\(\dfrac{2}{5}\cdot x=4\)

\(x=4:\dfrac{2}{5}=>x=10\)

. là dấu nhân nhé

b)

\(\dfrac{8}{7}:x=\dfrac{4}{5}\)

\(x=\dfrac{8}{7}:\dfrac{4}{5}=>x=\dfrac{10}{7}\)

\(\left(2\dfrac{2}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)

\(=\left(\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)

\(=\dfrac{9}{85}:\left(-\dfrac{3}{17}\right)=-\dfrac{3}{5}\)