HOC24
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Môn học
Chủ đề / Chương
Bài học
`(7x-11)^3 =5^2 *2^5 +200`
`=>(7x-11)^3 =25*32+200`
`=>(7x-11)^3 =800+200`
`=>(7x-11)^3 =1000`
`=>(7x-11)^3 =10^3`
`=>7x-11=10`
`=>7x=10+11`
`=>7x=21`
`=>x=21:7`
`=>x=3`
`3^x -2^3 =3^0`
`=>3^x -8=1`
`=>3^x =1+8`
`=> 3^x =9`
`=>3^x =3^2`
`=>x=2`
ấy chết=)))
\(C=\sqrt{14-8\sqrt{3}}-\sqrt{21-12\sqrt{3}}\)
\(=\sqrt{2\left(7-4\sqrt{3}\right)}-\sqrt{12-2\cdot2\sqrt{3}\cdot3+9}\)
\(=\sqrt{2}\cdot\sqrt{4-2\cdot2\cdot\sqrt{3}+3}-\sqrt{\left(\sqrt{12}-3\right)^2}\)
\(=\sqrt{2}\cdot\sqrt{\left(2-\sqrt{3}\right)^2}-\left|2\sqrt{3}-3\right|\)
\(=\sqrt{2}\cdot\left|2-\sqrt{3}\right|-\left(2\sqrt{3}-3\right)\) (vì \(2\sqrt{3}-3>0\) )
\(=\sqrt{2}\cdot\left(2-\sqrt{3}\right)-2\sqrt{3}+3\) (vì \(2-\sqrt{3}>0\) )
\(=2\sqrt{2}-\sqrt{6}-2\sqrt{3}+3\)
\(a-6\sqrt{a}+9-b^2\\ =\left(\sqrt{a}+3\right)^2-b^2\\ =\left(\sqrt{a}+3-b\right)\left(\sqrt{a}+3+b\right)\)
\(x-9=\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)\)
\(x-7\sqrt{x}+12\\ =x-4\sqrt{x}-3\sqrt{x}+12\\ =\sqrt{x}\left(\sqrt{x}-4\right)-3\left(\sqrt{x}-4\right)\\ =\left(\sqrt{x}-4\right)\left(\sqrt{x}-3\right)\)
\(x\sqrt{x}+64\\ =\sqrt{x^3}+4^3\\ =\left(\sqrt{x}\right)^3+4^3\\ =\left(\sqrt{x}+4\right)\left(x-4\sqrt{x}+16\right)\)
\(ĐKXD:\left\{{}\begin{matrix}2x^2+5x-3\ge0\\2x-1\ge0\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}2x^2+6x-x-3\ge0\\2x\ge1\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}2x\left(x+3\right)-\left(x+3\right)\ge0\\x\ge\dfrac{1}{2}\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}\left(x+3\right)\left(2x-1\right)\ge0\\x\ge\dfrac{1}{2}\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}\left[{}\begin{matrix}\left\{{}\begin{matrix}x+3\ge0\\2x-1\ge0\end{matrix}\right.\\\left\{{}\begin{matrix}x+3\le0\\2x-1\le0\end{matrix}\right.\end{matrix}\right.\\x\ge\dfrac{1}{2}\end{matrix}\right.\)
\(< =>\left\{{}\begin{matrix}\left[{}\begin{matrix}\left\{{}\begin{matrix}x\ge-3\\x\ge\dfrac{1}{2}\end{matrix}\right.\\\left\{{}\begin{matrix}x\le-3\\x\le\dfrac{1}{2}\end{matrix}\right.\end{matrix}\right.\\x\ge\dfrac{1}{2}\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}\left[{}\begin{matrix}x\ge\dfrac{1}{2}\\x\le-3\end{matrix}\right.\\x\ge\dfrac{1}{2}\end{matrix}\right.\\ < =>\left\{{}\begin{matrix}x\le-3\\x\ge\dfrac{1}{2}\end{matrix}\right.\)
a)
`(2x-3)(x+4)>2(x^2 +1)`
`<=>2x^2 +8x-3x-12>2x^2 +2`
`<=>5x>14`
`<=>x>14/5`
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`0` `14/5`
b)
`(3x-1)/2-(5x+1)/3>4`
`<=>(9x-3)/6-(10x+2)/6>24/6`
`<=>9x-3-10x-2>24`
`<=>-x>29`
`<=>x<-29`
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-29 0