Nguyên hàm từ 0 đến pi/6 của (1-sin2x+cos2x)/(sinx-cosx)dx

\(\int_0^{\dfrac{\pi}{6}}\)\(\dfrac{1-sin2x+cos2x}{sinx-cos2x}dx\)

\(\int_0^{\dfrac{\pi}{2}}\)\(\dfrac{1+sin2x}{sinx+cosx}dx\)

a) \(\int_{\dfrac{\pi}{8}}^{\dfrac{2\pi}{8}}\)\(\dfrac{dx}{sin^2xcos^2x}\)

b) \(\int_{\dfrac{\pi}{6}}^{\dfrac{\pi}{3}}\)\(\dfrac{cos2xdx}{sin^2xcos^2x}\)

c) \(\int_0^{\dfrac{\pi}{3}}\)\(\dfrac{cos3x}{cosx}\)dx

\(\int_{\dfrac{\pi}{4}}^{\dfrac{\pi}{3}}\)\(\dfrac{2cos2x+5}{sin^2x}dx\)