theo đề ta có: \(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\) và x + y - z = 10

          => \(\frac{x}{8}=\frac{y}{12};\frac{y}{12}=\frac{z}{15}\)

          =>  \(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)

áp dụng t/x DTSBN ta có:

\(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)= \(\frac{x+y-z}{8+12-15}=\frac{10}{5}=2\)

=> \(\hept{\begin{cases}\frac{x}{8}=2\\\frac{y}{12}=2\\\frac{z}{15}=2\end{cases}}\)

=> \(\hept{\begin{cases}x=16\\y=24\\z=30\end{cases}}\)

vậy x = 16 ; y = 24 ; z = 30

chúcbạn học giỏi!! ^^

ok mk nhé!! 565464565764574686856952352345346545676576856363463464575675675683434