C

B

\(a,\dfrac{1}{2}\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{1}{6}-\dfrac{1}{8}=\dfrac{4}{24}-\dfrac{3}{24}=\dfrac{1}{24}\\ b,\dfrac{5}{2}:\dfrac{1}{4}-\dfrac{1}{8}=\dfrac{5}{2}\times4-\dfrac{1}{8}=10-\dfrac{1}{8}=\dfrac{80}{8}-\dfrac{1}{8}=\dfrac{79}{8}\)

\(y\times\dfrac{2}{5}=\dfrac{4}{7}:\dfrac{3}{2}\\ y\times\dfrac{2}{5}=\dfrac{8}{21}\\ y=\dfrac{8}{21}:\dfrac{2}{5}\\ y=\dfrac{20}{21}\\ \dfrac{12}{7}:y+\dfrac{2}{5}=\dfrac{7}{5}\\ \dfrac{12}{7}:y=\dfrac{7}{5}-\dfrac{2}{5}\\ \dfrac{12}{7}:y=1\\ y=\dfrac{12}{7}:1\\ y=\dfrac{12}{7}\\ \)

B

\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\\ =1-\left(\dfrac{1}{2}-\dfrac{1}{2}\right)-\left(\dfrac{1}{3}-\dfrac{1}{4}\right)-...-\left(\dfrac{1}{99}-\dfrac{1}{99}\right)-\dfrac{1}{100}\\ =1-0-0-...-0-\dfrac{1}{100}\\ =1-\dfrac{1}{100}\\ =\dfrac{99}{100}\)

10.B

11.C

B