đề là gì vậy bạn

\(\dfrac{3}{5}+\dfrac{6}{11}+\dfrac{7}{13}+\dfrac{2}{5}+\dfrac{16}{11}+\dfrac{19}{13}\\ =\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{6}{11}+\dfrac{16}{11}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)\\ =\dfrac{5}{5}+\dfrac{22}{11}+\dfrac{26}{13}\\ =1+2+2\\ =5\)

câu b sai ở đâu v?

nhìn mãi chẳng ra lỗi 

sai

C sai r có dấu chấm phẩy ở do kìa

sai r

\(\dfrac{3}{2}\times\dfrac{4}{7}+\dfrac{3}{7}\times\dfrac{3}{2}\\ =\dfrac{3}{7}\times\dfrac{4}{2}+\dfrac{3}{7}\times\dfrac{3}{2}\\ =\dfrac{3}{7}\times\left(\dfrac{4}{2}+\dfrac{3}{2}\right)\\ =\dfrac{3}{7}\times\dfrac{7}{2}\\ =\dfrac{3}{2}\)

\(13,25:0,5+13,25:0,2+13,25:0,25\\ =13,25\times2+13,25\times5+13,25\times4\\ =13,25\times\left(2+5+4\right)\\ =13,25\times11\\ =145,75\)

\(\left(x-5\right)\left(x-1\right)=\left(2x+1\right)\left(\dfrac{1}{2}x-3\right)\\ \Leftrightarrow x^2-6x+5=x^2-\dfrac{11}{2}x-3\\ \Leftrightarrow x^2-6x+5-x^2+\dfrac{11}{2}x+3=0\\ \Leftrightarrow-\dfrac{1}{2}x+8=0\\ \Leftrightarrow x=16\)