HOC24
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\(a,\dfrac{5}{6}x\dfrac{1}{3}=\dfrac{5}{18}\\ b,\dfrac{5}{6}:\dfrac{1}{3}=\dfrac{5}{2}\\ c,\dfrac{5}{3}-\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{5}{3}-\dfrac{4}{3}=\dfrac{1}{3}\)
a, \(\dfrac{3}{5}:\dfrac{3}{4}=\dfrac{3}{5}x\dfrac{4}{3}=\dfrac{12}{15}\)
b, \(\dfrac{2}{5}:\dfrac{3}{10}=\dfrac{2}{5}x\dfrac{10}{3}=\dfrac{4}{3}\)
c, \(\dfrac{1}{8}:\dfrac{1}{6}=\dfrac{1}{8}x\dfrac{6}{1}=\dfrac{3}{4}\)
Tìm x: \(\left(x-\dfrac{1}{5}\right):\left(x-1\dfrac{6}{7}\right)< 0\)
Tìm giá trị của biểu thức bt: \(a=\dfrac{2021}{2022},b=\dfrac{2023}{2022}\\ B=\dfrac{\dfrac{2ab}{3}-\dfrac{3ab}{2}}{\dfrac{-5bb}{6}}\)