Ta có:

\(4n+3⋮2n+1\)

\(\Rightarrow\left(4n+2\right)+1⋮2n+1\)

\(\Rightarrow2\left(2n+1\right)+1⋮2n+1\)

\(\Rightarrow1⋮2n+1\)

\(\Rightarrow2n+1\in U\left(1\right)=\left\{-1;1\right\}\)

\(\Rightarrow\left\{{}\begin{matrix}2n+1=-1\Rightarrow n=-1\\2n+1=1\Rightarrow n=0\end{matrix}\right.\)

Vậy \(n\in\left\{-1;0\right\}\)

A=(1;2;3;4;6;12)

tick nha bạn

6 chia hết cho x-1 =>x-1 = { 1;2;3;6}=>x={2;3;4;7}

\(-8+2\left|2x-3\right|=4\)

\(\Leftrightarrow2\left|2x-3\right|=4-\left(-8\right)\)

\(\Leftrightarrow2\left|2x-3\right|=4+8\)

\(\Leftrightarrow2\left|2x-3\right|=12\)

\(\Leftrightarrow\left|2x-3\right|=12:2\)

\(\Leftrightarrow\left|2x-3\right|=6\)

Xét trường hợp 1: \(2x-3=6\)

\(\Rightarrow2x=6+3\)

\(\Rightarrow2x=9\)

\(\Rightarrow x=9:2\)

\(\Rightarrow x=\dfrac{9}{2}\)

Xét trường hợp 2: \(2x-3=-6\)

\(\Rightarrow2x=-6+3\)

​\(\Rightarrow2x=-\left(6-3\right)\)​

\(\Rightarrow2x=-3\)

\(\Rightarrow x=-3:2\)

\(\Rightarrow x=\dfrac{-3}{2}\)

Vậy \(x=\dfrac{9}{2}\) hoặc \(x=\dfrac{-3}{2}\)

có tất cả 100 điểm 10

Mk nghj̉ thế

a) \(x^4-8x\)

\(=x\left(x^3-8\right)\)

\(=x\left(x-2\right)\left(x^2+2x+4\right)\)

b) \(x^2-5x+10y-4y^2\)

\(=\left(x^2-4y^2\right)-\left(5x-10y\right)\)

\(=\left(x-2y\right)\left(x+2y\right)-5\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x+2y-5\right)\)

c) \(9y^2-4x^2+4x-1\)

\(=9y^2-\left(4x^2-4x+1\right)\)

\(=\left(3y\right)^2-\left(2x-1\right)^2\)

\(=\left(3y-2x+1\right)\left(3y+2x-1\right)\)

\(\dfrac{x}{x-3}+\dfrac{9-6x}{x^4-3x}\)

\(=\dfrac{x\left(x^4-3x\right)}{\left(x-3\right)\left(x^4-3x\right)}+\dfrac{\left(9-6x\right)\left(x-3\right)}{\left(x-3\right)\left(x^4-3x\right)}\)

\(=\dfrac{x\left(x^4-3x\right)+\left(9-6x\right)\left(x-3\right)}{\left(x-3\right)\left(x^4-3x\right)}\)

\(=\dfrac{x^5-3x^2+9x-27-6x^2+18}{\left(x-3\right)\left(x^4-3x\right)}\)

\(=\dfrac{x^5-9x^2+9x-9}{\left(x-3\right)\left(x^4-3x\right)}\)

Diễm cho thảo nguyên và thu uyên tất cả số ngôi sao là:

50x2=100(ngôi sao)

Diễm còn lại số  ngôi sao là:

129-100=29(ngôi sao )

              đáp số :29 ngôi sao