\(-8+2\left|2x-3\right|=4\)
\(\Leftrightarrow2\left|2x-3\right|=4-\left(-8\right)\)
\(\Leftrightarrow2\left|2x-3\right|=4+8\)
\(\Leftrightarrow2\left|2x-3\right|=12\)
\(\Leftrightarrow\left|2x-3\right|=12:2\)
\(\Leftrightarrow\left|2x-3\right|=6\)
Xét trường hợp 1: \(2x-3=6\)
\(\Rightarrow2x=6+3\)
\(\Rightarrow2x=9\)
\(\Rightarrow x=9:2\)
\(\Rightarrow x=\dfrac{9}{2}\)
Xét trường hợp 2: \(2x-3=-6\)
\(\Rightarrow2x=-6+3\)
\(\Rightarrow2x=-\left(6-3\right)\)
\(\Rightarrow2x=-3\)
\(\Rightarrow x=-3:2\)
\(\Rightarrow x=\dfrac{-3}{2}\)
Vậy \(x=\dfrac{9}{2}\) hoặc \(x=\dfrac{-3}{2}\)
-8+2.|2.x-3|=4
2.|2.x-3|=4-(-8)
2.|2.x-3|=12
|2.x-3|=12:2
|2.x-3|=6
TH1:2.x-3=6
2.x=6+3
2.x=9
x=9:2
x=4,5
TH2:2.-3=-6
2x=-6+3
2x=-3
x=-3:2
x=-1,5
-8+2.|2.x-3|=4
2.|2.x-3|=4-(-8)
2.|2.x-3|=12
|2.x-3|=12:2
|2.x-3|=6
TH1:2.x-3=6
2.x=6+3
2.x=9
x=9:2
x=4,5
TH2:2.-3=-6
2x=-6+3
2x=-3
x=-3:2
x=-1,5
-8+2.|2x-3|=4
⇒2.|2x-3|=4-(-8)=4+8
⇒2.|2x-3|=12
⇒|2x-3|=12:2=6
⇒\(\left\{{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2x=6+3=9\\2x=-6+3=-3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{9}{2}\\x=\dfrac{-3}{2}\end{matrix}\right.\)
Vậy x∈{\(\dfrac{9}{2}\);\(\dfrac{-3}{2}\)}