điền từ thích hợp :
at least , comfortable, flexible, easy , mall , remote , victim , with , advance , without
a) School regulations have to be ...................... in the countryside , so in some ................... schools students do not always wear uniforms
b) To do well in test , study .............. a week in ...................
c) ....................... treatment , a sanake - bite ................... will go into shock and die
d) It is more .......................... to shop in the ........................ than in the other shopping areas.
1) viết lại câu :
a) Walking on the grass in forbidden . It is ...............................
b) "Make good use of your time , Hoa " Minh said ................................................
c) I would like you to help me empty the basket. Do you mind ...................................
2) điền từ :
a) Her sister is charecter is different .......... hers.
b) I look forward ............ hearing your reply
c) I am bored ........... this program . when will is finish ?
3) tìm và sửa lỗi sai :
a) everyone have his own dreams about his future
b) I feel very pride to be a part of this football team
c) they do morning exercise so as improve their health
d) could you help me how solve this problem
4) điền từ :
a) I am not good ......... speaking English . I speak English ...............
b) When my granddad ........... still alive , he .......... to tell us stories
a) \(x-\dfrac{\dfrac{x}{2}-\dfrac{3+x}{4}}{2}=\dfrac{2x-\dfrac{10-7x}{3}}{3}-\left(x-1\right)\)
b) \(x^2-6x-2+\dfrac{14}{x^2-6x+7}=0\)
c) \(\dfrac{8x^2}{3\left(1-4x^2\right)}=\dfrac{2x}{6x-3}-\dfrac{1+8x}{4+8x}\)
d) \(\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}=\dfrac{6}{x^2-9}\)
e) \(\left(1-\dfrac{2x-1}{x+1}\right)^3+6\left(1-\dfrac{2x-1}{x+1}\right)^2=\dfrac{12\left(2x-1\right)}{x+1}-20\)
1) giải pt :
a) \(\dfrac{7x+10}{x+1}\left(x^2-x-2\right)-\dfrac{7x+10}{x+1}\left(2x^2-3x-5\right)=0\)
b) \(\dfrac{13}{2x^2+x-21}+\dfrac{1}{2x+7}+\dfrac{6}{9-x^2}=0\)
c) \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)
d) \(\dfrac{1+\dfrac{x}{x+3}}{1-\dfrac{x}{x+3}}=3\)