1 . Tính
a . \(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + ... + \(\dfrac{1}{9.10}\)
= 1 - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + ... + \(\dfrac{1}{9}\) - \(\dfrac{1}{10}\)
= 1 - \(\dfrac{1}{10}\)
= \(\dfrac{9}{10}\)
b . \(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ... + \(\dfrac{1}{99.100}\)
= 1 - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{4}\) + ... + \(\dfrac{1}{99}\) - \(\dfrac{1}{100}\)
= 1 - \(\dfrac{1}{100}\)
=\(\dfrac{99}{100}\)
2 . Tìm x , biết :
a . \(\dfrac{2}{5}\) + \(\dfrac{4}{5}\)x - \(\dfrac{7}{5}\) = \(\dfrac{9}{5}\)
\(\dfrac{2}{5}\) - \(\dfrac{7}{5}\) + \(\dfrac{4}{5}\)x = \(\dfrac{9}{5}\)
-1 + \(\dfrac{4}{5}\)x = \(\dfrac{9}{5}\)
\(\dfrac{4}{5}\)x = \(\dfrac{9}{5}\) + 1 ( Quy tắc chuyển vế )
\(\dfrac{4}{5}\)x = \(\dfrac{14}{5}\)
=> 4.x = 14
=> x = 14 : 4
=> x = 3,5
b . \(\dfrac{2}{5}\)x - \(\dfrac{6}{4}\) = \(\dfrac{8}{5}\)
\(\dfrac{2}{5}\)x = \(\dfrac{8}{5}\) + \(\dfrac{6}{4}\)
\(\dfrac{2}{5}\)x = \(\dfrac{31}{10}\)
x = \(\dfrac{31}{10}\) : \(\dfrac{2}{5}\)
x = \(\dfrac{31.5}{10.2}\)
x = \(\dfrac{31.1}{2.2}\)
x = \(\dfrac{31}{4}\)