\(a\)) \(\dfrac{6}{2x+1}=\dfrac{2}{7}\)
\(\Leftrightarrow2\left(2x+1\right)=6\cdot7\)
\(\Leftrightarrow4x+2=42\)
\(\Leftrightarrow4x=40\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
\(b\)) \(\dfrac{24}{7x-3}=\dfrac{-4}{25}\)
\(\Leftrightarrow-4\left(7x-3\right)=24\cdot25\)
\(\Leftrightarrow-4\left(7x-3\right)=600\)
\(\Leftrightarrow7x-3=-150\)
\(\Leftrightarrow7x=-147\)
\(\Leftrightarrow x=-21\)
Vậy \(x=-21\)
\(c\)) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\)
Ta có: \(\dfrac{4}{x-6}=\dfrac{-12}{18}\)
\(\Leftrightarrow-12\left(x-6\right)=72\)
\(\Leftrightarrow x-6=-6\)
\(\Leftrightarrow x=0\)
\(\dfrac{y}{24}=\dfrac{4}{x-6}\)
\(\Leftrightarrow\dfrac{y}{24}=\dfrac{-2}{3}\)
\(\Leftrightarrow y=\dfrac{-2}{3}\cdot24\)
\(\Leftrightarrow y=-16\)
Vậy \(x=0\)
\(y=-16\)
\(d\)) \(-\dfrac{1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\)
\(\Leftrightarrow-0,2\le x\le0,25\)\(\)
Mà \(x\in Z\)
\(\Leftrightarrow x=0\)
Vậy \(x=0\)
\(e\)) \(\dfrac{x+46}{20}=x\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{x+46}{20}=\dfrac{5x+2}{5}\)
\(\Leftrightarrow5\left(x+46\right)=20\left(5x+2\right)\)
\(\Leftrightarrow5x+230=100x+40\)
\(\Leftrightarrow5x-100x=40-230\)
\(\Leftrightarrow-95x=-190\)
\(\Leftrightarrow x=\dfrac{-190}{-95}\)
\(\Leftrightarrow x=2\)
Vậy \(x=2\)
\(f\)) \(y\dfrac{5}{y}=\dfrac{56}{y}\)
\(\Leftrightarrow\dfrac{y^2+5}{y}=\dfrac{56}{y}\)
\(\Leftrightarrow\left(y^2+5\right)y=56y\)
\(\Leftrightarrow y^3+5y=56y\)
\(\Leftrightarrow y^3=56y-5y\)
\(\Leftrightarrow y^3=51y\)
\(\Leftrightarrow\dfrac{y^3}{y}=51\)
\(\Leftrightarrow y^2=51\)
\(\Leftrightarrow y=\sqrt{51}\)
\(\Leftrightarrow y=7,141...\)
Mà \(y\in Z\)
Vậy \(y\) không có giá trị