HOC24
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\(\left\{{}\begin{matrix}P+E+N=52\\P=E\\N-E=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2E+N=52\\N-E=1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}N=18\\P=E=Z=17\end{matrix}\right.\\ \Rightarrow A=Z+N=18+17=35\left(đ.v.C\right)\\ KH:^{35}_{17}Cl\)
\(C_6H_{12}O_6⇌\left(men.rượu,30-35^oC\right)2C_2H_5OH+2CO_2\\ CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\\ n_{CO_2}=n_{Ca\left(OH\right)_2}=\dfrac{15}{100}=0,15\left(mol\right)\\ n_{C_6H_{12}O_6\left(LT\right)}=\dfrac{0,15}{2}=0,075\left(mol\right)\\ m=m_{C_6H_{12}O_6\left(TT\right)}=0,075.180=13,5\left(g\right)\)
\(n_{H_2SO_4}=0,05.0,4=0,02\left(mol\right)\\ n_{HCl}=0,2.0,35=0,07\left(mol\right)\\ \left[H^+\right]=\dfrac{0,02.2+0,07}{0,05+0,35}=0,275\left(M\right)\\ pH=-log\left[H^+\right]=-log\left[0,275\right]=0,56\\ \Rightarrow Qùy.hóa.đỏ\)