= 43                                          

Mình nghĩ đề là \(x^2-10x+y^2+6y+34=-16z^2+8z-1\)

\(x^2-10x+y^2+6y+34=-16z^2+8z-1\)

\(\left(x^2-10x+25\right)+\left(y^2+6y+9\right)+\left(16z^2-8z+1\right)=0\)

\(\left(x-5\right)^2+\left(y+3\right)^2+\left(4z-1\right)^2=0\)

\(\Rightarrow x-5=0,y+3=0\) và \(4z-1=0\)

Vậy \(x=5,y=3\) và \(z=\frac{1}{4}\)

đề có sai không zậy bạn?

Ta có:a(a+1)(a+2)(a+3)=570024=26.27.28.29

=>a+a+1+a+2+a+3=26+27+28+29=110

Put the word in their correct order. (Sắp xếp các từ theo đúng trật tự.)

1. do / what / she / does / ?

=> What does she do?

2. school / I / and / this / my / student / am / a / is

=> I am a student and this is my school.

3. eraser / that / is / your / ?

=> Is that your eraser?

4. Mai's class / students / are / twenty / in / there

=> There are twenty students in Mai's class.

5. book / where / my / is ?

=> Where is my book?

\(x^3+ax+b\\ =x^3+x^2-x^2-x+x+ax+b\\ =x^2\left(x+1\right)-x\left(x+1\right)+7+\left(a+1\right)x+\left(b-7\right)\)

Ta có: \(x^2\left(x+1\right)-x\left(x+1\right)+7\) chia \(\left(x+1\right)\) dư 7

\(\Rightarrow\left(a+1\right)x+\left(b-7\right)\) chia hết cho \(\left(x+1\right)\)

Đến đây, đồng nhất hệ số ta được: \(a+1=1\) và \(b-7=1\)

\(\Rightarrow a=0\) và \(b=8\)

a^x : a^y = a^x-y

a^x . a^y = a^x+y

\(\Leftrightarrow3^4+2^x=25+2^2.3.5\)

\(\Leftrightarrow81+2^x=25+60\)

\(\Leftrightarrow81+2^x=85\)

\(\Leftrightarrow2^x=4\)

\(\Leftrightarrow2^x=2^2\)

\(\Rightarrow x=2\)