:)) tớ quên 

\(\left|3x-1\right|=2x-3\\ \Rightarrow\left[{}\begin{matrix}3x-1=2x-3\\3x-1=3-2x\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3x-2x=1-3\\3x+2x=1+3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-2\\5x=4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-2\\x=\dfrac{4}{5}\end{matrix}\right.\)

phân số cuối là \(\dfrac{2}{7}-\dfrac{2\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}\) nha :vv

\(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{1\dfrac{1}{6}-\dfrac{7}{8}+0,7}\\ =\dfrac{2\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{\dfrac{2}{6}-\dfrac{2}{8}+\dfrac{2}{10}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\\ =\dfrac{2}{7}-\dfrac{2\left(\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{10}\right)}{7\left(\dfrac{1}{6}-\dfrac{1}{8}-\dfrac{1}{10}\right)}\\ =\dfrac{2}{7}-\dfrac{2}{7}=0\)

.-. mik bt mà , lúc ý mik nhìn nhầm 

\(\left(\dfrac{1}{3}+3x\right)\left(-2x+8\right)=0\\ \Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}+3x=0\\-2x+8=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x=-\dfrac{1}{3}\\-2x=-8\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{9}\\x=4\end{matrix}\right.\)

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