a) = (\(\dfrac{1}{2}-\dfrac{1}{2}\))+\(\dfrac{3}{4}\)
    =0+\(\dfrac{3}{4}\)
    =\(\dfrac{3}{4}\)

\(\dfrac{2008}{1}\)+\(\dfrac{2007}{2}\)+\(\dfrac{2006}{3}\)+...+\(\dfrac{2}{2007}\)+\(\dfrac{1}{2008}\)

E=\(2^{100}\)-\(2^{99}\)-\(2^{98}\)-...-\(2^2\)-2-1

2A = 1 + \(\dfrac{1}{2}\)+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{2^3}\)+...+\(\dfrac{1}{2^{99}}\)

2A - A= 1- \(\dfrac{1}{2^{100}}\)

A= 1