Var k,i,t:longint;
Function kt(n:longint):boolean;
Var s,x:string;
    d,m,j:longint;
Begin
s:='';
x:='';
j:=0;
d:=0;
 While n<>0 do
  Begin
   d:=n mod 2;
   n:=n div 2;
   Str(d,s);
   x:=x+s;
   j:=length(x)
  end;
s:=x;
For m:=1 to j do
 x[m]:=x[j-m+1];
If s=x then Exit(True) else Exit(False);
end;
Begin
{$ifndef online_JUDGE}
Assign(input,'standard.inp');
 Reset(input);
Assign(output,'standard.out');
 Rewrite(output);
{$endif}
Read(k);
For i:=1 to k+1 do
 Begin
  If kt(i-1) then inc(t);
 end;
Write(t);
end.

Ta có x+y+z=4

=>y=4-x-z

Ta có :x,y,z>0

=>\(x^2>0,z^2>0\)

=>\(x^2z>0,z^2x>0\)

Áp dụng bất đẳng thức cô si với hai số dương \(x^2z\) và z ta có

      \(x^2z+z\)>=2\(\sqrt{x^2z.z}\)

<=>\(x^2z+z>=2xz\)

CMTT:\(z^2x+x>=2xz\)

=>\(x^2z+z+z^2x+x>=4xz\)

=>\(x+z>=4xz-x^2z-z^2x\)

=>\(x+z>=xz\left(4-x-z\right)\)

Mà y=4-x-z(cmt)

=>\(x+z>=xyz\)

=>\(\dfrac{x+z}{xyz}>=1\)

hay \(P>=1\)

Dấu "=" xảy ra <=> \(\left\{{}\begin{matrix}x^2z=z\\z^2x=x\\x+y+z=4\end{matrix}\right.\)

                        <=>\(\left\{{}\begin{matrix}x^2=1\\z^2=1\\x+y+z=4\end{matrix}\right.\)  

                        <=>\(\left\{{}\begin{matrix}x=1\\z=1\\1+y+1=4\end{matrix}\right.\)

                        <=>\(\left\{{}\begin{matrix}x=1\\z=1\\y=2\end{matrix}\right.\)

Vậy tại x=1, y=2,z=1 thì P có giá trị nhỏ nhất là 1

\(\dfrac{\left(-2\right)^3.9^3.5^5.7.8}{3^6.4^4.25^3.14}=-\dfrac{2^3.\left(3^2\right)^3.5^5.7.2^3}{3^6.\left(2^2\right)^4.\left(5^2\right)^3.7.2}=-\dfrac{2^6.3^6.5^5.7}{2^9.3^6.5^6.7}=-\dfrac{1}{2^3.5}=-\dfrac{1}{40}\)

24.15x2.4=57.96

34.78+23.25=58.03

=> chỉ có 1 số là 58

1.Salim went to school alone, ____although____ she knew that it was very unsafe.

2. They liked their camping holiday, ____in spite____ of the rain.

3. ____Despite____ the pain in her leg, she still won the marathon excellent.

4. My father decided to buy the car ____Although____ he didn’t really have enough money.

5. ___Although____ she was very sick, she still tried to complete this job.

6. ____Despite____ his age, he still plays badminton every morning.

7. _____Although___ Land and Mike went to university together, they weren’t close friend.

8. We still play football outside ____In spite___ of the heavily rain.

9. _____Despite___ her illness, she must go to school.

10. Loan knew what he wanted ___in spite_____ of not understanding anything.

11 ___Although___ the story of the film was good, I didn’t like the acting.

12. I went to see the film __despite____ feeling really tired.

13. I really enjoyed the Water War___although___ most of my friends said it wasn’t a very good film.

14.___Despite___ careful preparation, they had a lot of difficulties in making the film. 

certainty

moderm advertisements contain..hidden..messages , .implicit...in the advertisement showing the pretty girl in the new car or the..smiling...children round the packet of washing powder is the message that if we buy the product ,we also achieve...success... and happiness . it is a subtle approach since it seeks to...exploit.... our secrect dreams ,and it is inescapable since advertising is ubiquitous.they brainwash us into ..believing... that we can realize our ambitions quickly and easily ,on the other hand ,defenders of advertising say that it is..beneficial...Advertising is informative .Advertisement tell us about useful new.....products....They .brighten... our lives with color and music . whether for or against advertising ,most people would agree that some kind of watch-dog body , appointed by the..goverment... or by the advertising industry itself , is necessary to maintain the standards of ..honesty.... and to discourage the more blatant types of misleading advertisement

Var a,n:longint;
Begin
{$ifndef online_JUDGE}
Assign(input,'standard.inp');
 Reset(input);
Assign(output,'standard.out');
 Rewrite(output);
{$endif}
Read(a,n);
If n>=0 then
 Begin
  a:=a+n;
  If a>12 then a:=a-12;
 end
 else
 Begin
  a:=a-n;
  IF a<0 then a:=12-a*(-1);
 end;
Write(a);
end.

Viết bằng pascal dc k

a)\(\dfrac{-5}{6};\dfrac{-3}{4};\dfrac{7}{24};\dfrac{2}{3};\dfrac{7}{8};\dfrac{16}{17}\)

b)\(\dfrac{20}{23};\dfrac{205}{107};\dfrac{214}{315};\dfrac{7}{10};\dfrac{-5}{8};\dfrac{-16}{19}\)