\(\left[\left(3^{14}\times69+3^{14}\times12\right):3^{16}-7\right]:2^4\)

\(=\left[3^{14}\left(69+12\right):3^{16}-7\right]:2^4\)

\(=\left[3^{14}.81:3^{16}-7\right]:2^4\)

\(=\left[3^{14}.3^4:3^{16}-7\right]:2^4\)

\(=\left[3^2-7\right]:2^4\)

\(=2:2^4\)

\(=\dfrac{2}{16}=\dfrac{1}{8}\)

Cảm ơn bạn :>

\(D=1+3+3^2+3^3+3^4+...+3^{2022}\)

\(3D=3.\left(1+3+3^2+3^3+3^4+...+3^{2022}\right)\)

\(3D=3+3^2+3^3+3^4+3^5+...+3^{2023}\)

\(3D-D=\left(3+3^2+3^3+3^4+3^5+...+3^{2023}\right)-\left(1+3+3^2+3^3+3^4+...+3^{2022}\right)\)

\(2D=\left(3^{2023}-1\right)\)

\(D=\left(3^{2023}-1\right):2\)

Ta có:

\(5^{102}=5^{2.51}=\left(5^2\right)^{51}=25^{51}\)

\(\Rightarrow5^{102}=25^{51}\)

What time do you have breakfast?

\(\Rightarrow\) Bắt đầu bằng What

\(S=7+7^2+7^3+...7^{20}\)

Ta có: \(7S=7.\left(7+7^2+7^3+...+7^{20}\right)\)

\(7S=7^2+7^3+7^4+...+7^{21}\)

\(7S-S=\left(7^2+7^3+7^4+...+7^{21}\right)-\left(7+7^2+7^3+...+7^{20}\right)\)

\(6S=\left(7^{21}-7\right)\)

\(S=\left(7^{21}-7\right):6\)

Chúc bạn học tốt