\(f\left(2004\right)=\left(\frac{1}{3}-\frac{8}{2004}\right).3\)
\(=1-\frac{24}{2004}\)
\(=\frac{1980}{2004}=\frac{165}{167}\)
\(f\left(x\right)=\left(\frac{1}{3}-\frac{8}{x}\right).3=2004\)
\(\Leftrightarrow\frac{1}{3}-\frac{8}{x}=668\)
\(\Leftrightarrow\frac{8}{x}=-\frac{2003}{3}\)
\(\Leftrightarrow-2003.x=24\)
\(\Leftrightarrow x=\frac{-24}{2003}\)
Mình không chắc lắm, nếu có gì sai sót, mn nói với mình nha!
f(2004) = (1/3-8/2004) .3
=1-24/2004
=1980/2004=165/167
f(x)=(1/3-8/x).3=2004
⇌1/3-8/x=668
⇌8/x=-2003/3
⇌-2003.x=24
⇌x=-24/2003
