\(\Leftrightarrow x^2+x-x^2+4x-4=0\)
=>5x-4=0
hay x=4/5
\(x\left(x+1\right)-\left(x-2\right)^2\)
\(=x^2+x-\left(x^2-4x+4\right)\)
\(=x^2+x-x^2+4x-4\)
\(=x+4x-4\)
\(=5x-4\)
\(\Leftrightarrow x^2+x-x^2+4x-4=0\)
=>5x-4=0
hay x=4/5
\(x\left(x+1\right)-\left(x-2\right)^2\)
\(=x^2+x-\left(x^2-4x+4\right)\)
\(=x^2+x-x^2+4x-4\)
\(=x+4x-4\)
\(=5x-4\)
b. x( x – 4) - 2x + 8 = 0
c. x^2-25 –( x+5 ) = 0
d.(2x -1)^2- (4x2 – 1) = 0
e. ( 3x – 1)^2 – ( x +5)^2 = 0
f. x^3 – 8 – (x -2)(x -12) =0
Bài 3
1.(x-1)(x+2)+5x-5=0
2.(3x+5)(x-3)-6x-10=0
3.(x-2)(2x+3)-7x2+14x=0
4.(x+1)(x-3)-15+5x=0
5.5(2x-1)(x+3)+5x-10x2=0
Bài4
1.3x-6+(x+1)(x-2)=0
2.4x2+6x-(2x+3)(3x-x)=0
3.5x-10-(2-x)(4+x)=0
4.10-10x+(x-1)(x-3)=0
5.20x2+30x-2(x-5)(2x+3)=0
Tìm x biết:
a)(x+3)^2+(x-2)(x+2)-2(x+1)=7
b)x(2x-1)-(x-2)(2x+3)=0
c)(x-1)(x+2)-x-2=0
d)x[(3x+2)+(x+1)^2-(2x-5)(2x+5)]=0
đ) 2x^2-7x+5=0
e) (2x+3)(x-5)=(2x+1)(2×+3)
Đề: Tìm x
a)2x.(3x+5)-x.(6x-1)=33 k)5(x+3)-2x(x+3)=0
b)x(3x-1)+12x-4=0 i)5x(x-2)-(2-x)=0
c)5x(2x+1)-12x-6=0 m)x(x-1)-2(1-x)=0
d)x3-5x2+4x-20=0
e)2x3-5x2+2x-5=0
g)(x-2)3-x(x+1).(x-1)+62=5
a) 9x2-49=0
b) (x+3)(x2-3x+9)-x(x-1)(x+1)-27=0
c) (x-1)(x+2)-x-2=0
d) x(3x+2)+(x+1)2-(2x-5)(2x+5)=0
e) (4x+1)(x-2)-(2x-3)(2x-1)=7
Em cần gấp mong mọi người giúp đỡ
tìm x
a) x(x-2)-x+2=0
b) \(x^2\left(x^2+1\right)-x^2-1=0\)
c) 2x(x-3)-4x+12=0
d) \(9x^2-\left(2x+1\right)^2=0\)
a) x2(x - 5) + 5 - x = 0; b) 3x4 - 9x3 = -9x2 + 27x;
c) x2(x + 8) + x2 = -8x; d) (x + 3)(x2 -3x + 5) = x2 + 3x.
e) 3x(x - 1) + x - 1 = 0;
f) (x - 2)(x2 + 2x + 7) + 2(x2 - 4) - 5(x - 2) = 0;
g) (2x - 1)2 - 25 = 0;
h) x3 + 27 + (x + 3)(x - 9) = 0.
i)8x3 - 50x = 0; k) 2(x + 3)-x2 - 3x = 0;
m)6x2 - 15x - (2x - 5)(2x + 5) =
1.Tìm x:
a, x(x-2)+ x-2 = 0
b, (2x-1)2 - (x + 2)2 = 0
c, x3 -x = 0
Bài 1:
a) 2/3.x.(x2-4)= 0
b)(x+2)2-(x-2).(x+2)=0
c)x2+2x+1=0
Tìm x biết
a, 5x (x - 1) - (1 - x) = 0
b, (x - 3)2 - (2x + 3)2 = 0
c, 2x (x2 - 4) = 0
d, (x - 2)2 - (x - 2) (x + 3) = 6
e, x2 + 6x - 7 = 0