Đại số lớp 7
Các câu hỏi tương tự
s=\(\dfrac{2}{2^1}+\dfrac{3}{2^2}+\dfrac{4}{2^3}+...+\dfrac{n+1}{2^n}+...+\dfrac{2016}{2^{2015}}\)
xét tổng S gồm 2015 số hạng sau . Hay so sánh S với 3
Bài 1: a) Cho \(A=\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)...\left(\dfrac{1}{2015}-1\right)\left(\dfrac{1}{2016}-1\right)\). So sánh A với \(\dfrac{-1}{2015}\)
b) Cho biểu thức \(A=\dfrac{3x^3-x^2-3x+2015}{3x^4-x^3+3x+2014}\). Tính giá trị của biểu thức với x=\(\dfrac{1}{3}\)
2 tháng 4 2017 lúc 22:35
Cho :S=\(1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+.......+\dfrac{1}{2013}-\dfrac{1}{2014}+\dfrac{1}{2015}\) và P=\(\dfrac{1}{1008}+\dfrac{1}{1009}+......+\dfrac{1}{2014}+\dfrac{1}{2015}\) Tính \(\left(S-P\right)^{2016}\)
Tìm x biết :
a) \(\dfrac{3x+2}{5x+7}=\dfrac{3x-1}{5x+1}\)
b) \(\dfrac{x+1}{2016}+\dfrac{x}{2017}=\dfrac{x+2}{2015}+\dfrac{x+3}{2014}\)
c) (2x - 1 )2 = ( 2x - 1 )2018
d) ( x - 1 )x + 2 = ( x - 1 )x + 4
e) ( 2x - 3 )2 = 144
Tìm x:
\(\left(\dfrac{1}{2}+\dfrac{1}{3}+.....+\dfrac{1}{2014}\right)x=\dfrac{2013}{1}+\dfrac{2012}{2}+.....+\dfrac{2}{2012}+\dfrac{1}{2013}\)
Tính tổng sau:
\(\dfrac{1}{2}+\dfrac{2}{4}+\dfrac{3}{8}+\dfrac{4}{16}+...+\dfrac{10}{2^{10}}\)
Cho A= 1 + \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{4034}\); B = 1 + \(\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{7}+...+\dfrac{1}{4033}\)
So sánh \(\dfrac{A}{B}\)với 1\(\dfrac{2017}{2018}\)
M=(\(\dfrac{0,4-\dfrac{2}{9}+\dfrac{2}{11}}{1,4-\dfrac{7}{9}+\dfrac{7}{11}}\)-\(\dfrac{\dfrac{1}{3}-0,25+\dfrac{1}{5}}{1\dfrac{1}{6}-0,875+0,7}\)):\(\dfrac{2014}{2015}\)
Tìm x
a)\(\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}=\dfrac{x+1}{13}+\dfrac{x+1}{14}\)
b)\(\dfrac{x+4}{2014}+\dfrac{x+3}{2015}=\dfrac{x+2}{2016}+\dfrac{x+1}{2017}\)
CẢM ƠN CÁC BẠN NHÌU ^_^