\(\left[\left(x+\dfrac{1}{3}\right).\dfrac{3}{4}+5\right]\): 2 = 3
\(\left(x+\dfrac{1}{3}\right).\dfrac{3}{4}\) + 5 = 3 . 2
\(\left(x+\dfrac{1}{3}\right).\dfrac{3}{4}\) + 5 = 6 \(\left(x+\dfrac{1}{3}\right).\dfrac{3}{4}\) = 6 - 5 \(\left(x+\dfrac{1}{3}\right).\dfrac{3}{4}\) = 1 \(\left(x+\dfrac{1}{3}\right)\) = 1 : \(\dfrac{3}{4}\) \(x+\dfrac{1}{3}\) = \(\dfrac{4}{3}\) => \(x=\dfrac{4}{3}-\dfrac{1}{3}\) => \(x=1\)
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Bạn tách từng phần ra nha, mk viết nhầm
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[(x+13).34+5][(x+13).34+5]: 2 = 3
(x+13).34(x+13).34 + 5 = 3 . 2
(x+13).34(x+13).34 + 5 = 6 (x+13).34(x+13).34 = 6 - 5 (x+13).34(x+13).34 = 1 (x+13)(x+13) = 1 : 3434 x+13x+13 = 4343 => x=43−13x=43−13 => x=1
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